Question
Pipes D, E, and F can fill a tank in 8 hours, 4 hours, and 16 hours respectively. If the efficiencies of D and E are each reduced by 50% of their original efficiency and all three pipes are opened together, find the total time taken by them to fill the tank.
Solution
ATQ, Let the capacity of the tank (LCM of 8, 4, and 16) be 16 liters. Efficiency of pipe D = 16/8 = 2 liters/hour Efficiency of pipe E = 16/4 = 4 liters/hour Efficiency of pipe F = 16/16 = 1 liter/hour New efficiency of pipe D = 2 × (50/100) = 1 liter/hour New efficiency of pipe E = 4 × (50/100) = 2 liters/hour Total efficiency = 1 + 2 + 1 = 4 liters/hour Required time = 16 / 4 = 4 hours
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