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    Question

    Pipes X, Y, and Z can fill a tank in 12 hours, 6 hours,

    and 8 hours respectively. If the efficiencies of pipes X and Y are each reduced by 50% of their original efficiency and all three pipes are opened together, find the total time taken to fill the tank.
    A 10 hrs Correct Answer Incorrect Answer
    B 4 hrs Correct Answer Incorrect Answer
    C 12 hrs Correct Answer Incorrect Answer
    D 18 hrs Correct Answer Incorrect Answer

    Solution

    ATQ, Let the capacity of the tank (LCM of 12, 6, and 8) be 24 liters. Efficiency of pipe X = 24/12 = 2 liters/hour Efficiency of pipe Y = 24/6 = 4 liters/hour Efficiency of pipe Z = 24/8 = 3 liters/hour New efficiency of pipe X = 2 × (50/100) = 1 liter/hour New efficiency of pipe Y = 4 × (50/100) = 2 liters/hour Total efficiency = 1 + 2 + 3 = 6 liters/hour Required time = 24 / 6 = 4 hours

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