Question
Tap A is 50% more efficient than tap B. Both the taps
together can fill the tank in (48/5) hours. Find the time taken by tap C, which is 60% more efficient than tap B, to fill the tank alone.Solution
Let, time taken by tap B to fill the tank be x hours,
So, time taken by tap A to fill the tank = x/1.5 hours According to question,
1/x + 1/(x/1.5) = 1/(48/5)
1/x + 1.5/x = 5/48
x = (48 × 2.5)/5 = 120/5 = 24 So, time taken by tap C to fill the tank = 24/1.6 = 15 hours
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