Start learning 50% faster. Sign in now
ATQ,
Let the total capacity of the container = L.C.M of 20 and 25 = 100 units
So, efficiency of pipe 'X' alone = 100 ÷ 20 = 5 units/minute
Combined efficiency of pipes 'X' and 'Y' = 100 ÷ 25 = 4 units/minute
So, efficiency of pipe 'Y' alone = 4 - 5 = -1 unit/minute (outlet)
So, time taken by pipe 'Y' alone to empty 60% of the container = (100 × 0.6) ÷ 1 = 60 minutes
81% of 2300 – 34% of 550 = ?
(25 + 12) x 6 + 34 = ? + 18
15% of 360 × 20% of ? = 324
(122 - 82 ) X ? = 90% of 500 - (90 - 25) X 2
√289 + √49 + 121 =?
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
√3598 × √(230 ) ÷ √102= ?
1.55 + 2.05 + 1.5 × 11 – 20% of 10.5 = ?
72% of 400 – 23% of 1020 = 120% of ?
120% of 400 + ?% of 520 = 1000