Question
There are two pipes A & B, pipe A is for filling the
swimming pool and pipe B is to empty the swimming pool. Capacity of swimming pool is 15120 m 3  and volume of pipe B is 24 m 3 /minute more than that of pipe A. If pipe A takes 11(1/4) more minutes to fill same swimming pool, than time taken by B to empty the same swimming pool. If pipe B can empty second swimming pool in 112.5 minutes, then find the capacity of second swimming pool?(m 3 )Solution
Let capacity of pipe A = x m3 So, capacity of pipe B = x+ 24 m3 Required time to fill the swimming pool = 15120/x minutes  Required time to empty the swimming pool = 15120/ (x + 24) minutes According to question – 15120/x – 15120 (x + 24) = 45/4 336/x – 336/ (x + 24) = 1/4 By solving, x = 168 m3 Capacity of second swimming pool = (168 + 24) × 100.5 = 19296m3
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