Let the total capacity of tank be 45 units Efficiency of pipe ‘A’ = 45/15 = 3 units/hour Efficiency of pipe ‘B’ = 45/45 = 1 units/hour Tank filled in 2 hours = (3 – 1) = 2 units Therefore, tank filled in (2 × 13.5 = 27 hours) = 2 × 13.5 = 27 units Required percentage of tank filled = (27/45) × 100 = 60%
Design suitable for one of the factor need larger plot and another smaller plot is
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