Question
Pipe βAβ can fill a tank in 15 hours while pipe
βBβ can empty it in 45 hours. They were operated on alternate hours starting with pipe βAβ. Find the percentage of tank filled this way in 27 hours.Solution
Let the total capacity of tank be 45 units Efficiency of pipe βAβ = 45/15 = 3 units/hour Efficiency of pipe βBβ = 45/45 = 1 units/hour Tank filled in 2 hours = (3 β 1) = 2 units Therefore, tank filled in (2 Γ 13.5 = 27 hours) = 2 Γ 13.5 = 27 units Required percentage of tank filled = (27/45) Γ 100 = 60%
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