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Start learning 50% faster. Sign in nowIn a single roll of dice, there are 6 numbers i.e. 1, 2, 3,4,5,6. Total possible outcomes in rolling 3 dices= 6× 6 ×6 = 216 & the cases without showing 3 number (means every dice will show number 1, 2, 4,5,6only) = 5× 5×5 = 125 So no. of possible outcomes in which at least one of the die shows number 3 = Total Possible outcomes – cases without showing 3 number = 216 – 125 = 91
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