Four dice are rolled simultaneously. What is the number of possible outcomes in which at least one of the die shows 2?
In a single roll of dice, there are 6 numbers i.e. 1, 2, 3,4,5,6. Total possible outcomes in rolling 4 dices= 6× 6 ×6×6 = 1296 & the cases without showing 2 number (means every dice will show number 1, 3,4,5,6only) = 5× 5×5×5 = 625 So no. of possible outcomes in which at least one of the die shows number 2 = Total Possible outcomes – cases without showing 2 number = 1296 – 625 = 671
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