Question
A team of 4 men and 2 women is to be selected out of 8
men and 4 women. If only one man and one woman remain in the team, then what will be the total number of possibilities?Solution
Total men =8 and Women =4 If only one man and one woman live in the team, then total number of possibilities = =7C3 ×3C1 =35×3=105
More Permutation and combination Questions
3 4.5 6.75 10.125 15.1875 22.78125 ?
...If   43         34    x          36        39          38
Then,  (x/2)  + 0.5 + x  = ?
...23   27    54    ?       195    231
...[(288)2 ÷ 96 × ?] ÷ 44 = 432
5 11 32 65 ? 389
...1 4 13 46 ? 976
...44 23 21 34.5 ? 167.5
...27   44    63    86   ?      146
3, 4, 10, 33, 136, ?, 4116
32, 65 , 196, 785, ? , 23557
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