Question
A team of 4 men and 2 women is to be selected out of 8
men and 4 women. If only one man and one woman remain in the team, then what will be the total number of possibilities?Solution
Total men =8 and Women =4 If only one man and one woman live in the team, then total number of possibilities = =7C3 ×3C1 =35×3=105
More Permutation and combination Questions
5555.05 + 500.05 + 5000.005 + 5.005 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?) for given equation.Â
(47.98 × 34.85 ÷ 7.09) – (80.81 ÷ 9.02 × 5.01) = ?
...
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
(1120.45 ÷ 15.89) × 11.34 = ? × 4.78
What will be the approximate value of the following questions.
(√143.74 + 29.89% of 720.27) × (5/9 of 539.79) = ?
320.98 + 49.99% of (261.09 + 138.98) = ?
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