Question
In a group of 9 boys and 6 girls, 5 students have to be
selected. In how many ways it can be done so that only 2 boys are included.Solution
=> 9C2 × 6C3 = [9!/(9 -2)! 2!] × [6!/(6 -3)! 3!] => [9!/7! 2!] × [6!/3! 3!] => 720 ways
4 ? 113 449 1343 2681
...14 15 34 116 460 2325
...There are three series given below which are following with the same pattern.
Series I: 21, 44, 135, 544, 2725
Series II: 14, B, C, D, E
40    42    87    266    ?     5366
3 2 10 ? 17 16
...91   93   97   100   ?   113
11, 12, 16, 25, ?, 66
1 5 36 343 ? 59049
...2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
59, 170, 301, 452, ?, 814