Question
In an exam, a candidate scoring
28% marks fails by 24 marks, while another candidate scoring 40% marks gets 36 marks more than the pass marks. Find the maximum marks and the pass marks.Solution
ATQ,
Let total marks = M and pass marks = P. From first candidate: 28% of M is 24 less than P ⇒ 0.28M + 24 = P …(1) From second candidate: 40% of M is 36 more than P ⇒ 0.40M − 36 = P …(2) Equate (1) and (2): 0.28M + 24 = 0.40M − 36 24 + 36 = 0.40M − 0.28M 60 = 0.12M M = 60 / 0.12 = 500 Put M = 500 in (1): P = 0.28 × 500 + 24 = 140 + 24 = 164 Hence, Maximum marks = 500, Pass marks = 164.
What will come in the place of question mark (?) in the given expression?
?% of 192 = 242 – 48 × 11
What will come in the place of question mark (?) in the given expression?
45% of (√6400 × 5) = ? + 111
- What will come in place of (?), in the given expression.
√2025 + 35% of 400 = ? 15% of 695 – 12.5% of 250 =? – 1200
7, 8, 12, 21, 37, ?
22 – 15 + 20 × 18 ÷ 6 – 34 = ?
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
[(1245 ÷ 9) ÷ 12] × 540 = ?2 – 175
Simplify the following expression
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