Question
In an exam, a candidate scoring
28% marks fails by 24 marks, while another candidate scoring 40% marks gets 36 marks more than the pass marks. Find the maximum marks and the pass marks.Solution
ATQ,
Let total marks = M and pass marks = P. From first candidate: 28% of M is 24 less than P ⇒ 0.28M + 24 = P …(1) From second candidate: 40% of M is 36 more than P ⇒ 0.40M − 36 = P …(2) Equate (1) and (2): 0.28M + 24 = 0.40M − 36 24 + 36 = 0.40M − 0.28M 60 = 0.12M M = 60 / 0.12 = 500 Put M = 500 in (1): P = 0.28 × 500 + 24 = 140 + 24 = 164 Hence, Maximum marks = 500, Pass marks = 164.
(76.98% of 599.98) ÷ 20.99 = ? + 7.98% of 199.99
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