Question
The price of a product P was increased by 60% and then
decreased by 25%. After these changes, the prices of products P and Q are in the ratio 9:7. If the difference between their prices is Rs. 64, what was the initial price of product P?Solution
ATQ,
Let initial price of P = x After +60% and -25% → final price = 1.6x × 0.75 = 1.2x Given ratio P:Q = 9:7 and difference = 64 ⇒ 2 parts = 64 ⇒ 1 part = 32 ⇒ P(final) = 9×32 = 288 So 1.2x = 288 ⇒ x = 240 Initial price of P = Rs. 240
More Percentage Questions
- What will come in place of (?) in the given expression.
(18.5 × 2) + (3.5 × 4) = ? If x + y + 3 = 0, then find the value of x3 + y3 – 9xy + 9.
40% of 50 + 50% of ? = 25% of 300 - 10% of 250
√10000 x √8100 - (50)² = √(?) + (80)²
1428 ÷ 17 = ? % of 120
- Identify x such that x% of 540 plus {1080 ÷ x of 9} × 6 gives 162
Simplify the following expression:
Simplify the expression:
(9x² - 25) / (3x + 5)
135 ÷ 3 of 5 = ? - 112
