Question
In a qualifying test, the passing marks are 60%. Marks obtained by ‘G’ are 5% less than passing marks, and ‘H’ scores 28% marks less than G. What percent less (up to 2 decimal places) than the sum of G’s and H’s marks should I obtain to pass the exam at the borderline?
Solution
ATQ,
Let the maximum marks = 100x
Passing marks = 60x
G’s score = (60x)(1 – 0.05) = 57x
H’s score = (57x)(1 – 0.28) = 41.04x
Sum of the scores of ‘G’ and ‘H’ = 57x + 41.04x = 98.04x
Required percentage = {(98.04x – 60x)/98.04x} × 100 = 38.79%
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