Question
In a college election, two candidates competed. One
candidate secured 62% of the total votes and won the election by a margin of 1,020 votes. Assuming all votes were valid, what percentage of the total votes received by the losing candidate corresponds to the total votes obtained by the winning candidate?Solution
ATQ, 62/100 * x – 38/100 * x = 1020 0.24x = 1020 x = 4250 Total votes got by other candidate = 38/100 * 4250 = 1615 Total votes got by winning candidate = 62/100 * 4250 = 2635 Required % = 1615/2635 * 100 = 61.2%
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
I. 15y2 + 26y + 8 = 0
II. 20x2 + 7x – 6 = 0
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 135 = 0
Equation 2: y² - 26y + 153 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
