Question
If the length of a rectangle is increased by 60%, what
would be the percentage decrease (correct to the nearest integer) in the width to maintain the same area?Solution
Let the length and width of the rectangle =100 Area =100×100=10000. Length after 50% increase length =160 And let the x% decrease in width =(100-x) Area =(100-x) ×160. ATQ- (100-x) ×160 =10000 16x =600 x=37.5%(approx.) Required Answer=100-37.5 =62.5% Â
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