Question
The income of βAβ increases by 20% every year. If
his income 3 years hence from now will be Rs. 51840, then find his income a year before from now.Solution
Let the present income of βAβ be Rs. x Therefore, x(1 + 20/100)3 = 51840 Or, x = 51840/(1.2)2 = 30000 Therefore, his income a year before from now = 30000/1.2 = Rs. 25000
What will be the output of the code
int main(){
int x= 10;
int y=10;
int s=-(-x-y)
cout<
return 0;
}
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