Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 85000 which is 4 times the monthly income of βCβ. If βAβ spends 75% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 18900, then find the savings of βAβ.Solution
Monthly income of βCβ = 85000/4 = Rs. 21250 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (63750 β x) According to the question, 0.25x + 0.20(63750 β x) = 18900 Or, 0.05x = 6150 x = 123000 Or, savings of βAβ = 0.25x = Rs. 30750
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 41.92% of 49.96% of (45.07 1.97 β 4.98 2.03 )
(15.15Β Γ Β 31.98) + 30.15% of 719.99 = ? + 124.34
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
784.69 + 86.96Β Γ· 29.01 = 40.01 + ? + 367.88
(29.892 Γ β290) + 32.98 Γ 6.91 = ?
(15.87% of 79.98 + 19.69% of 64.22) Γ 4.83 = ?
Β (3/5) of 3025 + (18Β² + 12Β²) = ? + 22.22% of 1125
24.75% of 20.125% of 30.05% of 2196.06 = ?Β
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
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