Question
A person sells each package of snacks for Rs. 20 each.
On Monday, he sold 100 packages which was 20 more than that on Tuesday but 10 less than that on Wednesday. If he spends 80% of his income earned by selling snack packages on these 3 days, then find his saving in given 3 daysSolution
Number of packages of snack sold on Monday = 100 Number of packages of snack sold on Tuesday = 100 – 20 = 80 Number of packages of snack sold on Wednesday = 100 + 10 = 110 Therefore, his total income of 3 days = (100 + 80 + 110) × 20 = 290 × 20 = Rs. 5800 Therefore, savings of person in given 3 days = 0.20 × 5800 = Rs. 1160
Determine the value of k such that the points A(2,3), B(4,k), and C(6,-3) lie on the same straight line.
Solve the given equation for ?. Find the approximate value.
(3/5 of 399.78 + 7/9 of 360.15) ÷ (√63.94 + 25% of 383.94) = ?
...[{(√785) % of 449.85}/(35.89 × 7.14 + 849.89 ÷ 5.12 + 199.78% of 41.09)] = ( 1/? )Â
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What will come in place of the question mark (?) in the following series?
50, 25, 25, ?, 75, 187.5
What approximate value will replace the question mark (?) in the following?
? + 1...
