Question
A certain number of students from school X appeared in
an examination and 30% students failed. 150% more students than those from school X. appeared in the same examination from school Y. If 80% of the total number of students who appeared from X and Y passed, then what is the percentage of students who failed from Y?Solution
Let number of students in school X be 100x Number of failed students in school X = 30% of 100x = 30x Number of passes students in school Y = (100x – 30x) = 70x Number of students in school Y = 100x + 150% of 100x = 100x + 150x = 250x Total number of students in school X and school Y = 100x + 250x = 350x Number of passes students in both schools = 80% of 350x = 280x So, number of passed students in school Y = 280x – 70x = 210x Number of failed students in school Y = 250x – 210x = 40x Percentage of failed students in school Y = (40x/250x) × 100% = 16% ∴ The percentage of students who failed from school Y is 16%
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(17.17 ×  21.98) + 34.15% of 649.99 = ? + 125.34
7480 ÷ 16.98 – 34.32 ÷ (4.99/99.9) = ?
89.87 × 3.21 + 60.32 = ? × (6.89 2 – 19.21)Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
What approximate value will replace the question mark (?) in the following?
39.99...
13.99% of 299.99 ÷ 7.17 = ? ÷ 16.15
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
