Question

A gets 36% of the full marks in an exam and fails by 90 marks. B gets 38% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?

Q: A gets 36% of the full marks in an exam and fails by 90 marks. B gets 38% of the full marks in the s

Let maximum marks = 100x &there4; 36x + 90 = 38x + 72 => 2x = 18 => x = 9 &there4; Max marks = 100x = 900 &there4; Minimum percentage marks to be pass = {[(36×9) + 90]/900} × 100 = 46%

A 55

B 44

C 60

D 57

E 46

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Question

A gets 36% of the full marks in an exam and fails by 90 marks. B gets 38% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?

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