Question
A gets 36% of the full marks in an exam and fails by 90
marks. B gets 38% of the full marks in the same exam and he also fails by 72 marks. What is the minimum percentage of marks a student should obtain to pass the exam?Solution
Let maximum marks = 100x ∴ 36x + 90 = 38x + 72 => 2x = 18 => x = 9 ∴ Max marks = 100x = 900 ∴ Minimum percentage marks to be pass = {[(36×9) + 90]/900} × 100 = 46%
More Percentage Questions
- Find the value of the expression:
32 + 6 β 5 Γ [18 + 10 β 3 Γ (36 β 21)] β? = 32% of 900 + 48% of 50
Β Β
721 +21 x 9 - 118 = ? + 82
779 + 136 – 334 = 270 + 121 + ?
Find the value of.
( β β 343 )3 Γ ( β β216 )3
?= β(4 Γ β(16 Γ β(4 Γ β(16 Γβ¦β¦ β)) ) )Β
0.25 x 696 Γ· 0.3 = ?
33 + (6.25) % of 1600 = ? + 2 X 55
((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...What will come in the place of question mark (?) in the given expression?
(17/27) of 162 + ?Β² = 632 - (73 - 12) X 5
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