Question

A gave 40% of the amount he had to B. B gave 2/5th of what he received from A to C. After paying Rs. 260 to the taxi driver out of the amount he gets from B, C is now left with Rs. 1500. How much amount did A have?

Q: A gave 40% of the amount he had to B. B gave 2/5th of what he received from A to C. After paying Rs.

Let A’s amount be x. C now having the amount of Rs. 1500, => [x × (40/100) × (2/5)] – 260 = 1500 => x × (40/100) × (2/5) = 1760 => x = 1760/0.16 => x = 11000 A initially having an amount of Rs. 11000.

A 12000

B 10000

C 13000

D 11000

E None of these

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Question

A gave 40% of the amount he had to B. B gave 2/5th of what he received from A to C. After paying Rs. 260 to the taxi driver out of the amount he gets from B, C is now left with Rs. 1500. How much amount did A have?

Solution

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