Question
In a class of 40 students and 8 teachers, each student
got gifts that were 20% of total number of students and each teacher got gifts that were 15% of total number of students. How many gifts were there in total?Solution
Gifts received by each student = 20% of total number of students i.e. => 20/100 × 40 = 8 Gifts received by each teacher = 15% of total number of students i.e. => 15/100 × 40 = 6 Total Gifts = 40 × 8 + 6 × 8 = 368
I. p2 – 5p + 6 = 0                 Â
II. 36q2 = 81
...Solve: (x/3) + (x/5) = 16
 If the point of intersection of the lines 2x + y = 11 and x - y = 1 is P(a, b), then the value of a + 2b is:
Solve for x: 5x − 7 = 3x + 9
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
For given pair of equations, how many solutions are possible?
2x + 3y = 10 and 4x + 5y = 18
Solve: 2x + 3y = 19 and x − y = 2, Find x and y
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
Relevant for Exams:
