Question
X, Y, and Z join a partnership and invest some amount.
After one year, X doubles its investment, Y increases its investment by 33(1/3)%, and Z increases its investment by 20%. In the third year, X and Y withdraw their investments, and P joins the partnership with Z. After three years, they receive a profit in the ratio of 12:14:17:8 (X : Y : Z : P). If the difference between the initial investment of Y and Z is 3450, then find out the total initial investment made by X and P together.Solution
ATQ, Let investment of X, Y, Z and P is a, b, c and d respectively.  
X : Y : Z : D ⇒ (a × 12 + 2a × 12) : (b × 12 + 4 3 b × 12) : c × 12 + 26 5 c×12 : d × 12 3 a : 7b/ 3 : 17c/5 : d = 12 : 14 : 17 : 8 ⇒ a : b : c : d = 4 : 6 : 5 : 8 Difference between Y and Z initial investment = 3450  Total Investment of X and P together = (3450/1) × 12 = 41400  Â
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