Question
The investments of A and B in a partnership are Rs. 6000
and Rs. 10000. B withdraws 40% of initial investment after T months. If annual profit is Rs. 70000 and B received Rs. 40000 as share then find value of T.Solution
Investment of A = 6000 × 12 = Rs. 72000 Investment of B = 10000 × T + 6000 (12-T) ATQ: => 72000/(10000T + 72000 – 6000T) = (70000 – 40000)/40000 => 72/(10T + 72 – 6T) = 3/4 => 72/(4T + 72) = 3/4 => 96 = 4T – 72 => T = 24/4 = 6 months
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Out of the following quantity, which is required to irrigate 1.0 ha land area with 50mm depth of irrigation?
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