Question
Find the largest four-digit number which when divided
by 5, 7, 9, and 12, leaves a remainder 2, 4, 6, and 9 respectively.Solution
Here we can see that the difference (3) between numbers and remainder is same along all four numbers. 5 = 5¹
7 = 7¹
9 = 3²
12 = 2² × 3¹ LCM of (5, 7, 9, 12) = 2² × 3² × 5 × 7
= 4 × 9 × 5 × 7
= 1260 Largest four-digit number which is a multiple of 1260 = 8,820 So, the required number = 8820 − 3 = 8,817
 5983.987 + 59832.999 – 598.873 = ?
24.98% of 1682 × (18.2659 ÷ 9.04965)(–4) = ?Â
√81.02 + 11.836 of 24.98 = ?2 + 20.01
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[√ (121.23) ÷ √ (12100.04)] × √ 80.95 = 3/10 + ? ÷ 4
...63.95 – 21.12 – 24.89 + 6.04 = 3.98 × ? + 3.88
7480 ÷ 16.98 – 34.32 ÷ (4.99/99.9) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(9/10 of 3999.79) - √2499.83 + (17.81% of 1199.81) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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