Question
The addition of the average of two numbers and the third
number results in 270, 258 and 246 respectively. Find the required difference between max and min number.Solution
ATQ,
Let numbers be x, y, z. 2x + y + z = 270 × 2 = 540 x + 2y + z = 258 × 2 = 516 x + y + 2z = 246 × 2 = 492 4(x + y + z) = 540 + 516 + 492 = 1548 x + y + z = 387 x = 540 – 387 = 153 y = 516 – 387 = 129 z = 492 – 387 = 105 Difference = 153 – 105 = 48
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