Question
Find the least 4-digit number which, when divided by
21, 28, and 12, leaves a remainder of 3 in each case.Solution
Prime factorization of 21 = 3 × 7
Prime factorization of 28 = 2² × 7
Prime factorization of 12 = 2² × 3 LCM of (21, 28, and 12) = 2² × 3 × 7 = 84 Least 4-digit number divisible by 84 = 1,008 So, required number = 1008 + 3 = 1,011 Hence, option A.
Which organization launched the "Millets: Seeds of Change" digital exhibit?
Which river is considered the lifeline of Uttar Pradesh?
Where was the inaugural meeting of the Inland Waterways Development Council (IWDC) held?
Who is appointed as the Managing Director and CEO of Indian Overseas Bank which will come into effect from 1st January 2023?
The Union government and the Asian Development Bank (ADB) have signed a loan agreement to enhance fintech education in which city?
City of God is known as which of the following district of Uttar Pradesh?
How many women will be selected for the EmpowHER Biz initiative under the WEP of NITI Aayog?
Recently on 1st November,2022 India’s first data centre has been inaugurated by the Chief Minister of Uttar Pradesh Yogi Adityanath in ____...
What is the time limit for a player who stops dribbling in handball to either pass or shoot?
Recently which country passed New Transgender Bill that allows anyone to Change gender aged 16 and above?
