Question
Sum of digits of a two-digit number is 9. When 27 is
subtracted from the number, its digits get interchanged. Find the original number.Solution
ATQ, Let ones and tens digit of the number be a and b respectively. So, original number = 10b + a. Reverse number = 10a + b. So, a + b = 9 --------- (I) And, 10b + a − 27 = 10a + b. Or, 9b − 9a = 27. Or, b − a = 3 ---------- (II). On adding equation I and II, We get, a + b + b − a = 9 + 3. Or, 2b = 12. Or, b = 6. On putting value of b in equation I, We get, 6 + a = 9. Or, a = 3. Required number = 10 × 6 + 3 = 63.
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
(29.892 × √290) + 32.98 × 6.91 = ?
44.84% of 799.94 + (625.21 ÷ 24.91) – √(224.77) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
