Question
The sum of two numbers is 90 whereas the sum of their
reciprocals is (30/11). Find the square of the product of the two numbers.Solution
ATQ,
Let the two numbers be 'x' and 'y'.
So, x + y = 90
And (1/x) + (1/y) = (30/11)
Or, {(x + y)/(xy)} = (30/11)
Or, xy = (11/30) × 90 = 33
So, required square = 33² = 1089
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