Question
The smallest number 'Z' which when divided by 16, 24,
and 48 leaves 3 as the remainder in each case. Find the value of ('4Z' + 7).Solution
ATQ,
As we know the least number which is divisible by 'a', 'b', and 'c' is the LCM of 'a', 'b', and 'c'.
So, the number which is completely divisible by 16, 24, and 48 = LCM of
16, 24, and 48 = 48
So, 'Z' = 48 + 3 = 51
Now,
(4Z + 7) = (51 × 4) + 7 = 204 + 7 = 211
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