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    Question

    The six-digit number '83219y' is divisible by 6, but not by

    5. What is the value of (2y + 5)?
    A 12 Correct Answer Incorrect Answer
    B 18 Correct Answer Incorrect Answer
    C 13 Correct Answer Incorrect Answer
    D 10 Correct Answer Incorrect Answer

    Solution

    ATQ,

    For divisibility by 6, the number must be divisible by both 2 and 3.

    Sum of digits = 8 + 3 + 2 + 1 + 9 + y = 23 + y

    For divisibility by 3, (23 + y) must be divisible by 3.

    Also, y should be even (for divisibility by 2) and y ≠ 0 or 5 (to avoid divisibility by 5).

    Even digits: 0, 2, 4, 6, 8

    Trying values:

    23 + 4 = 27 → divisible by 3 ✅ and 4 is even ✅ → y = 4

    So, (2y + 5) = 2×4 + 5 = 13

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