Question
The digits of a two-digit number βNβ are reversed to
form a new number βMβ. If M < N and N β M = 63, then which of the following maybe βNβ?Solution
ATQ; Let the original number = N = β10a + bβ So, the new number = M = β10b + aβ ATQ; N = M + 63 So, 10a + b = 10b β a + 63 Or, 9a β 9b = 63 Or, a β b = 7 So, possible pairs of βaβ and βbβ = (9, 2), (8, 1) So, possible values of βNβ = 92, 81 Alternate Solution From option βaβ: N = 29 So, M = 92 Since, M > N {not possible} N = 81 So, M = 18 Also, N β M = 81 β 18 = 63
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