Question
A = (5/2) × B and C = (1/10) × A. If (A + B + C) =
255, then determine the value of (7C – B).Solution
ATQ; A = 10C And, A = (5/2) × B So, 10C = (5/2) × B Or, 4C = B Since, A + B + C = 255 So, 10C + 4C + C = 255 Or, 15C = 255 Or, C = 17 A = 17 × 10 = 170 And, B = 4 × 17 = 68 Required value = 7 × 17 – 68 = 51
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