Question
A = (5/2) × B and C = (1/10) × A. If (A + B + C) =
255, then determine the value of (7C – B).Solution
ATQ; A = 10C And, A = (5/2) × B So, 10C = (5/2) × B Or, 4C = B Since, A + B + C = 255 So, 10C + 4C + C = 255 Or, 15C = 255 Or, C = 17 A = 17 × 10 = 170 And, B = 4 × 17 = 68 Required value = 7 × 17 – 68 = 51
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x² - 8x + 15 = 0 ...
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
What are the coordinates of the point which divides the line joining (-1, 7) and (4, 3) in the ratio 2:3?
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
