Question
The ratio between the sum of the
digits of a two-digit number and that two-digit number is 1 : 5. If the digit in the unit's place is two less than the digit in the ten’s place, then find the 62% of the number.Solution
ATQ, Let ten's digit and unit's digit be x and (x-2) respectively Sum of digits = x + (x-2) = 2x – 2 Let the number be 10x + (x-2) = 11x - 2 (2x – 2) / (11x – 2) = 1/5 10x – 10 = 11x – 2 x = 8 Number is 86 Required number = 86 * 62/100 = 53.32
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