Question
Akhilesh has a collection of toys, and he tries
arranging them in different group sizes. Whenever he groups them in pairs (2s), triplets (3s), sets of four (4s), bundles of five (5s), or groups of six (6s), he always has one toy left over. However, when he arranges them in groups of seven (7s), there are no toys left ungrouped. What is the smallest number of toys Akhilesh could possibly have?Solution
L.C.M of (2, 3, 4, 5, 6) = 60
So according to the first condition total number of toys with Akhil = 60p + 1
Now according to the second condition, total number of toys = 7q
Since number of toys is same hence, 60p + 1 = 7q
When p = 5 then q = 43
Therefore minimum number of toys = 60 X 5 + 1 = 301
The questions below are based on the given Series-I. The series-I satisfies a certain pattern, follow the same pattern in Series-II and answer the ques...
4 5.5 19 .5 98.5 694 6251.5
...42 43 46 ...
203, 223, 198, 218, ?, 213
400 596 452 552 488 524
100 a �...
111 113 117 120 ? 133
85 135 172 ? 215 225
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
5 13 36 145 719 4321
84, 61, 80, 57, 76, ?
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