Question
In a certain pond, there are 60 more crabs than fish.
Unfortunately, 20% of the crabs have perished. Additionally, the pond has welcomed 80 new fish. As a result, the current ratio of crabs to fish is 3:4. Determine the original quantities of crabs and fish in the pond.Solution
Let the initial number of crabs in the pond be ‘x’ Therefore, initial number of fish in the pond = (x – 60) According to the question, 0.8x/(x – 60 + 80) = 3/4 Or, 3.2x – 3x = 60 Or, x = 60/0.2 = 300 Therefore, initial number of fish and crabs in the pond = (x + x – 60) = 540
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
Find the area between the lines 18x +12y = 108, 9x  + 6y  = 27, x - axis and y -axis.Â
If x - √3 y = 8 Find the slope in angle?
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
I. 2p2 + 5p + 2 = 0Â Â Â Â Â Â Â Â II. 2q2 + 11 q + 14 = 0
I. p2 – 5p + 6 = 0                 Â
II. 36q2 = 81
...The length of a line segment A, B is 10 units. The coordinates of point A are(2,3) and the value of ordinate of point B is 5. Then find the value of abs...
The equations 6x + my + 18 = 0 and 9x + 21y + 27 = 0 have a unique solution. Which of the following statements is definitely true?
I. p² - 365 = 364
II. q - √ 529 = √ 169
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