Question
Determine the 6052nd
term in the series 5,5,7,7,7,7,9,9,9,9,9,9,11,….Solution
ATQ,
Each term n is repeated n times. 5 is repeated twice, ending in the 2nd position. 7 is repeated four times, ending in the 6th position. 9 is repeated six times, ending in the 12th position, and so forth. When term 148 is repeated 148 times, The cumulative total reaches 6048. Thus, term 150 starts at the 6049th position and continues, So, the 6052nd term is 150.
What approximate value should replace the question mark?
12.45% of 640.20 − 60% of 2500 = ? − 9000.10
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
A, B & C have Rs.1550 together. If they divide the money in the ratio 1:3:1 respectively. Find the difference of amount received by B and C.
What approximate value should come in the place of (?) in the following questions?
∛(92.8 + √1025) * ? = 16.06% of 750
√1024.21 × √624.89 ÷ 4.98 + 11.99 × 4.01 = ?
√784 × 3 + (713.99 ÷ 6.98) = ?% of 619.99
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
