Question
Determine the 6052nd
term in the series 5,5,7,7,7,7,9,9,9,9,9,9,11,β¦.Solution
ATQ,
Each term n is repeated n times. 5 is repeated twice, ending in the 2nd position. 7 is repeated four times, ending in the 6th position. 9 is repeated six times, ending in the 12th position, and so forth. When term 148 is repeated 148 times, The cumulative total reaches 6048. Thus, term 150 starts at the 6049th position and continues, So, the 6052nd term is 150.
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