Question
The mean of three distinct numbers is 30. If the third
number is to the combined total of the first two numbers in the ratio 16:29, what is the sum of the first two numbers?Solution
Let 1st, 2ndĀ and 3rdĀ numbers be āAā, āBā and āCā, respectively Sum of all three numbers = 3 Ć 30 = 90 Given, C:(A + B) = 16:29 So, A + B = {29/(16 + 29)} Ć 90 = 58
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