Question
In an examination, the number of those who have passed
and the number of those who failed were in the ratio of 40 : 7. If 7 more had appeared and the number of failures was 8 less than earlier, the ratio of passers to failures would have been 35 : 4. Then find the original total number of students who appeared at the examination.Solution
Let number of passed students = 40x & that of failure students = 7x So total number of students = 40x+7x = 47x After admitting 7 more students, Total Students appeared = 47x+7 New Failure students = 7x-8 then new passed students = 47x+7 - (7x-8) = 40x+15 So ratio of new passed to new failure students = (40x+15) /(7x-8) = 35/4 160x + 60 = 245x - 280 85x = 340 x = 4 Total students appeared in the exam was = 47 × 4 = 188
Three series (I, II and III) are given below. Each series contain one odd one out (wrong term) . Wrong term in series I, III and II is denoted by 'P', '...
Two number series are given below, and both follow the same pattern. Series I contains a missing term (m + 18). Find the value of the missing term and ...
28         57           172           689          ?              20677
...112    162    199    ?     242    252
...16 9 ? 13.25 22.625 36.3125
...11, 12, 16, 25, ?, 66
94Â Â Â Â Â Â Â Â Â Â 282Â Â Â Â Â Â Â Â 284Â Â Â Â Â Â Â Â 852Â Â Â Â Â Â Â Â 856Â Â Â Â Â Â Â Â 2562
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
520Â Â 79Â Â 440Â Â 151Â Â Â 376Â Â Â ?
9999 6666 ? 2962.66 1975.11 1316. 74
...
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