Question
In an examination, the number of those who have passed
and the number of those who failed were in the ratio of 40 : 7. If 7 more had appeared and the number of failures was 8 less than earlier, the ratio of passers to failures would have been 35 : 4. Then find the original total number of students who appeared at the examination.Solution
Let number of passed students = 40x & that of failure students = 7x So total number of students = 40x+7x = 47x After admitting 7 more students, Total Students appeared = 47x+7 New Failure students = 7x-8 then new passed students = 47x+7 - (7x-8) = 40x+15 So ratio of new passed to new failure students = (40x+15) /(7x-8) = 35/4 160x + 60 = 245x - 280 85x = 340 x = 4 Total students appeared in the exam was = 47 × 4 = 188
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x² - 8x + 15 = 0 ...
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
What are the coordinates of the point which divides the line joining (-1, 7) and (4, 3) in the ratio 2:3?
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
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