Question

Sum of two digits of a two digit number is 11. When

Let the number be 10x y. ATQ, 10y x 10x - y 45 y x 5 ------ i x y 11 ------ ii Solving i and ii , we get x 3 and y 8 Therefore number 38

digits of the number are reversed then number formed is 45 more than the original number. Find the original number.

A 65

B 56

C 83

D 38

E None of these

Practice Next

More No. System Questions

6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
Simplify the following expressions and choose the correct option.

[(13)² − (9)²] × (5/8) = ?
(25 × 12 + 30 × 8 – 22 × 10) = ?
√1764 + 35 × 8 + 39 = ?²
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶
72 – 4(40 + 24 ÷ 6 × 6 – 4 × 4) + 40
36% of 250 – 18% of 200 = 30% of ?
32 of (16/8) of (30/24) of (120/x) = 30
What will come in place of (?), in the given expression.

(81 ÷ 9) + (121 ÷ 11) + (64 ÷ 8) = ?
Simplify:

0.48 ÷ 0.06 + 0.75 × (4/5)

Solution