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      Question

      In a group of three numbers first is double of second

      and half of third. The average of three numbers is 42. Find the difference between the first number and third number?
      A 34 Correct Answer Incorrect Answer
      B 36 Correct Answer Incorrect Answer
      C 26 Correct Answer Incorrect Answer
      D 28 Correct Answer Incorrect Answer

      Solution

      Let the first number be ‘x’ Second number = x/2 Third number = 2x According to the question, (x+x/2+2x)/3 = 42 (2x+x+4x)/6 = 42 7x = 42 × 6 x = 36 ∴ Required difference = 72 - 36 = 36

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