Question
A container has 30 litres of a solution of milk and
water in which water is 20% by volume. How many litres of water must be added so that water becomes 30% of the final mixture?Solution
Initial total = 30 L Water initially = 20% of 30 = 6 L Milk = 24 L Let x litres of water be added. New total volume = 30 + x New water volume = 6 + x Required water % = 30%: (6 + x) / (30 + x) = 0.30 6 + x = 0.30(30 + x) 6 + x = 9 + 0.3x x − 0.3x = 9 − 6 0.7x = 3 x = 3 / 0.7 = 30/7 Answer: 30/7 litres of water must be added.
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