Question
A container has 30 litres of a solution of milk and
water in which water is 20% by volume. How many litres of water must be added so that water becomes 30% of the final mixture?Solution
Initial total = 30 L Water initially = 20% of 30 = 6 L Milk = 24 L Let x litres of water be added. New total volume = 30 + x New water volume = 6 + x Required water % = 30%: (6 + x) / (30 + x) = 0.30 6 + x = 0.30(30 + x) 6 + x = 9 + 0.3x x − 0.3x = 9 − 6 0.7x = 3 x = 3 / 0.7 = 30/7 Answer: 30/7 litres of water must be added.
- What will come in place of the question mark (?) in the following questions?
300−40% of 200=? - Simplify the following expression:
16 + [17 - (8 + 11) + 6 - 3] ÷ 0.2 Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
2/9 of 5/8 of 3/25 of ? = 40
115 ÷ 23 + 12 × 6 = ? + 16 - 35
√? = 32% of 900 + 48% of 50
 Â
5/13 × 104 + 1(2/9) × 198 = 133 + ?
Simplify the following expressions and choose the correct option.
40% of 360 + 25% of 248 - 30
(11/12) × (18/22) × (4/3) + 3 = ?2
[(15)³ × (8)²] ÷ (90 × 6) = ?²