Question
A mixture contains alcohol and water in ratio 5:3. If 16
liters of mixture is removed and replaced with water, the new ratio becomes 1:1. Find the initial quantity of mixture.Solution
ATQ,
Let total = T Alcohol = 5T/8 Water = 3T/8 Removed 16 liters → alcohol removed = 5/8 × 16 = 10 water removed = 6 New alcohol = 5T/8 – 10 New water = 3T/8 – 6 + 16 Given: (5T/8 – 10) = (3T/8 + 10) Solve: 5T – 80 = 3T + 80 2T = 160 T = 80 liters
Which one of the following statements with regard to superintendence of Delhi Special Police Establishment is correct?
If at any time the Central Government is of opinion that Board unable to perform its functions, it may by notification, supersede the Board for such per...
Who is competent to issue a conditional order for removal of nuisance under section 133 of Cr.P.C?
National Institute of MH & NS v. C. Parameshwara discusses the scope of :
Any change in the name of the person indicated in the Memorandum of One Person Company as a nominee ________________________
What happens in a Mortgage by Conditional Sale under Section 58(c) of the Transfer of Property Act?
Where is the Secretariat of Codex Alimentarius Commission located?
The Delhi Special Police Establishment Act lays down that the members of the said police establishment shall have throughout any Union territory, in rel...
Under what article of the Constitution of India can the President take over the administration of a state in case its constitutional machinery breaks do...
Whoever, with the deliberate intention to wound religious feelings of any person. utter words or make any sound is liable for punishment under of the I...
