Question
A mixture contains alcohol and water in ratio 5:3. If 16
liters of mixture is removed and replaced with water, the new ratio becomes 1:1. Find the initial quantity of mixture.Solution
ATQ,
Let total = T Alcohol = 5T/8 Water = 3T/8 Removed 16 liters → alcohol removed = 5/8 × 16 = 10 water removed = 6 New alcohol = 5T/8 – 10 New water = 3T/8 – 6 + 16 Given: (5T/8 – 10) = (3T/8 + 10) Solve: 5T – 80 = 3T + 80 2T = 160 T = 80 liters
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