Question
A solution of acid and water of 400 liters is in the
ratio 9:11 (acid : water). If x liters of the mixture is taken out and replaced with water, the ratio of acid to water becomes 3:5. Find x?Solution
ATQ, Acid in the initial mixture = 400 * 9/(9 + 11) = 400 * 9/20 = 180 liters Water in the initial mixture = 400 – 180 = 220 liters (180 – x * 9/(9 + 11)) / (220 – x * 11/(9 + 11) + x) = 3/5 (180 – 9x/20) / (220 – 11x/20 + x) = 3/5 (180 – 9x/20) / (220 + 9x/20) = 3/5 5(180 – 9x/20) = 3(220 + 9x/20) 900 – 45x/20 = 660 + 27x/20 900 – 660 = 27x/20 + 45x/20 240 = 72x/20 240 = (72x)/20 x = 240 * 20 / 72 x = 4800 / 72 x = 200/3 x = 200/3 liters
In which direction is point N with respect to point L?
1- Creativity
2- Creation
3- Creature
4- Credential
5- Critique
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