Question
A 1000 ml mixture contains milk and water in the ratio
of 7:3. 10% of the mixture is removed and some water is added so that the new ratio of milk to water becomes 3:2. The amount of water added is what percent of the original mixture?Solution
Milk = 7/10 × 1000 = 700 ml Water = 300 ml Milk removed = 0.1 × 700 = 70 ml Water removed = 0.1 × 300 = 30 ml Remaining milk = 630 ml Remaining water = 270 ml Let water added = x ml 630 / (270 + x) = 3/2 ⇒ 1260 = 810 + 3x ⇒ 3x = 450 ⇒ x = 150 ml % = (150 / 1000) × 100 = 15%
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