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    Question

    Mixture A has milk and water in the ratio 3:2, while

    mixture B has them in the ratio 5:7. When both are mixed, the resulting mixture of 1320 ml has milk and water in the ratio of 61:73. What was the original quantity of mixture B?
    A 556 ml Correct Answer Incorrect Answer
    B 576 ml Correct Answer Incorrect Answer
    C 520 ml Correct Answer Incorrect Answer
    D 440 ml Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let milk and water in mixture A and B be 3x ml and 2x ml, and 5y ml and 7y ml respectively.

    Total quantity = 1320 ml

    Milk in 1320 ml = (61 / (61+73)) × 1320 = (61/134) × 1320 = 600 ml

    Water = 1320 – 600 = 720 ml

    So,

    3x + 5y = 600

    2x + 7y = 720

    Solving the equations:

    x = 60, y = 48

    So, quantity of mixture B = 5y + 7y = 12y = 12 × 48 = 576 ml

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