Question
A mixture consists of (k+16)
liters of milk and (2k+12) liters of water. After adding 8 liters of milk and 20 liters of water to the mixture, the ratio of milk to water becomes 3:5. Determine the initial total volume of the mixture.Solution
Let the final quantity of milk be '3y' litres
Final quantity of water = (5/3) X 3y = '5y' litres
So, (k + 16 + 8) :(2k + 12 + 20) = 3y:5y
Or, (k + 24) :(2k + 32) = 3:5
Or, 5 X (k + 24) = 3 X (2k + 32)
Or, 5k + 120 = 6k + 96
Or, 'k' = 24
Initial quantity of mixture = k + 16 + 2k + 12 = 3k + 28 = 3 X 24 + 28 = 100 litres
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â