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Let the final quantity of milk be '3y' litres
Final quantity of water = (5/3) X 3y = '5y' litres
So, (k + 16 + 8) :(2k + 12 + 20) = 3y:5y
Or, (k + 24) :(2k + 32) = 3:5
Or, 5 X (k + 24) = 3 X (2k + 32)
Or, 5k + 120 = 6k + 96
Or, 'k' = 24
Initial quantity of mixture = k + 16 + 2k + 12 = 3k + 28 = 3 X 24 + 28 = 100 litres
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