Question
A vessel initially holds 150 liters of pure milk. First,
30 liters of milk is taken out and replaced with an equal amount of water. The process is then repeated one more time, where again 30 liters of the mixture is removed and replaced with water. What is the final quantity of milk remaining in the vessel?Solution
Percentage of quantity of mixture removed each time = (30/150) × 100 = 20%
So, quantity of milk remaining in the vessel = 150 × {1 – (20/100)}2
= 150 × (0.8)2 = 150 × 0.64 = 96 litres
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