Question
"A 480-liter mixture of alcohol
and water has alcohol and water in the ratio of 5: p. When 20 liters of water are added, the new ratio of alcohol to water becomes 3:2. Determine the value of 'p'."Solution
ATQ, The quantity of alcohol in initial mixture = [5/(5 + p)] × 480 = 2400/(5 + p) Quantity of water in initial mixture = [p/(5 + p)] × 480 = 480p/(5 + p) According to question, {2400/(5 + p)} / [{480p/(5 + p)} + 20] = 3/2 2400/(500p + 100) = 3/2 1500p = 4800 – 300 = 4500 p = 4500/1500 p = 3
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