Question
200 liters of mixture 'M' (milk + water) contains milk
and water in the ratio of 1:3, respectively. In mixture 'N' of milk and water, the quantity of milk is 50% more than the quantity of water. 20% and 40% of mixtures 'M' and 'N', respectively, are mixed to form another mixture 'O', in which the quantity of milk is 8 liters less than the quantity of water. Find the initial quantity of milk and water in mixture 'N'.Solution
ATQ Ratio of milk and water in mixture 'N' = 3:2 Let the initial quantity of mixture 'N' be '80x' liters. In mixture 'O': Quantity of milk = (0.20×200×(1/4))+(0.40×80x×(3/5)) = (10+48x/5) litres Quantity of water = (0.20×200×(3/4))+(0.40×80x×(2/5)) = (30+32x/5) litres ATQ; 30 + 32x/5 - (10 + 48x/5) = 8 Or, 48x/5 - 32x/5 = 30 - 8 - 10 So, 'x' = (6/16) = 0.375 Therefore, initial quantity of mixture 'N' = '80x' = 80 x 0.375 = 30 liters
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