Question
200 liters of mixture 'M' (milk + water) contains milk
and water in the ratio of 1:3, respectively. In mixture 'N' of milk and water, the quantity of milk is 50% more than the quantity of water. 20% and 40% of mixtures 'M' and 'N', respectively, are mixed to form another mixture 'O', in which the quantity of milk is 8 liters less than the quantity of water. Find the initial quantity of milk and water in mixture 'N'.Solution
ATQ Ratio of milk and water in mixture 'N' = 3:2 Let the initial quantity of mixture 'N' be '80x' liters. In mixture 'O': Quantity of milk = (0.20×200×(1/4))+(0.40×80x×(3/5)) = (10+48x/5) litres Quantity of water = (0.20×200×(3/4))+(0.40×80x×(2/5)) = (30+32x/5) litres ATQ; 30 + 32x/5 - (10 + 48x/5) = 8 Or, 48x/5 - 32x/5 = 30 - 8 - 10 So, 'x' = (6/16) = 0.375 Therefore, initial quantity of mixture 'N' = '80x' = 80 x 0.375 = 30 liters
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44   45    41   50    ?      59    23
...221, 100, 0, -81, ?
...900 Â Â Â 90Â Â Â 18Â Â Â ? Â Â Â Â 2.16Â Â Â Â 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187
